Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in

$fs = mysql_query("SELECT * FROM `forso` WHERE `ids` = '" . $id . "'"); //Выбираю данные из таблы
while ($fs = mysql_fetch_array($fs))
{
echo '<a  href="test/?id=' . $fs['id'] . '">' . $fs['name'] .
'</a><br/><small><font color="#482CD1">' . $fs['opis'] . '</font></small><br/>';
}